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 * DO NOT ALTER OR REMOVE COPYRIGHT NOTICES OR THIS FILE HEADER.
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 * FITNESS FOR A PARTICULAR PURPOSE.  See the GNU General Public License
 * version 2 for more details (a copy is included in the LICENSE file that
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 * 2 along with this work; if not, write to the Free Software Foundation,
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/* @test
 * @bug 4531526
 * @summary Test that more than one debuggee cannot bind to same port
 *          at the same time.
 * @library /test/lib
 *
 * @build ExclusiveBind HelloWorld
 * @run driver ExclusiveBind
 */

import jdk.test.lib.process.ProcessTools;
import lib.jdb.Debuggee;

public class ExclusiveBind {
    /*
     * - Launch a debuggee with server=y,suspend=y
     * - Parse listening port
     * - Launch a second debuggee in server=y,suspend=n with the parsed port
     * - Second debuggee should fail with an error (address already in use)
     * - For clean-up we attach to the first debuggee and resume it.
     */
    public static void main(String args[]) throws Exception {
        // launch the first debuggee
        try (Debuggee process1 = Debuggee.launcher("HelloWorld").launch("process1")) {
            // launch a second debuggee with the same address
            ProcessBuilder process2 = Debuggee.launcher("HelloWorld")
                    .setSuspended(false)
                    .setAddress(process1.getAddress())
                    .prepare();

            // get exit status from second debuggee
            int exitCode = ProcessTools.startProcess("process2", process2).waitFor();

            // if the second debuggee ran to completion then we've got a problem
            if (exitCode == 0) {
                throw new RuntimeException("Test failed - second debuggee didn't fail to bind");
            } else {
                System.out.println("Test passed - second debuggee correctly failed to bind");
            }
        }
    }
}