1 /*
   2  * Copyright (c) 2000, 2013, Oracle and/or its affiliates. All rights reserved.
   3  * DO NOT ALTER OR REMOVE COPYRIGHT NOTICES OR THIS FILE HEADER.
   4  *
   5  * This code is free software; you can redistribute it and/or modify it
   6  * under the terms of the GNU General Public License version 2 only, as
   7  * published by the Free Software Foundation.
   8  *
   9  * This code is distributed in the hope that it will be useful, but WITHOUT
  10  * ANY WARRANTY; without even the implied warranty of MERCHANTABILITY or
  11  * FITNESS FOR A PARTICULAR PURPOSE.  See the GNU General Public License
  12  * version 2 for more details (a copy is included in the LICENSE file that
  13  * accompanied this code).
  14  *
  15  * You should have received a copy of the GNU General Public License version
  16  * 2 along with this work; if not, write to the Free Software Foundation,
  17  * Inc., 51 Franklin St, Fifth Floor, Boston, MA 02110-1301 USA.
  18  *
  19  * Please contact Oracle, 500 Oracle Parkway, Redwood Shores, CA 94065 USA
  20  * or visit www.oracle.com if you need additional information or have any
  21  * questions.
  22  */
  23 
  24 /**
  25  * @test
  26  * @bug 6840246 6559590
  27  * @summary test String.split()
  28  */
  29 import java.util.Arrays;
  30 import java.util.Random;
  31 import java.util.regex.*;
  32 
  33 public class Split {
  34 
  35     public static void main(String[] args) throws Exception {
  36         String source = "0123456789";
  37 
  38         for (int limit=-2; limit<3; limit++) {
  39             for (int x=0; x<10; x++) {
  40                 String[] result = source.split(Integer.toString(x), limit);
  41                 int expectedLength = limit < 1 ? 2 : limit;
  42 
  43                 if ((limit == 0) && (x == 9)) {
  44                     // expected dropping of ""
  45                     if (result.length != 1)
  46                         throw new RuntimeException("String.split failure 1");
  47                     if (!result[0].equals("012345678")) {
  48                         throw new RuntimeException("String.split failure 2");
  49                     }
  50                 } else {
  51                     if (result.length != expectedLength) {
  52                         throw new RuntimeException("String.split failure 3");
  53                     }
  54                     if (!result[0].equals(source.substring(0,x))) {
  55                         if (limit != 1) {
  56                             throw new RuntimeException(
  57                                 "String.split failure 4");
  58                         } else {
  59                             if (!result[0].equals(source.substring(0,10))) {
  60                             throw new RuntimeException(
  61                                 "String.split failure 10");
  62                             }
  63                         }
  64                     }
  65                     if (expectedLength > 1) { // Check segment 2
  66                        if (!result[1].equals(source.substring(x+1,10)))
  67                           throw new RuntimeException("String.split failure 5");
  68                     }
  69                 }
  70             }
  71         }
  72         // Check the case for no match found
  73         for (int limit=-2; limit<3; limit++) {
  74             String[] result = source.split("e", limit);
  75             if (result.length != 1)
  76                 throw new RuntimeException("String.split failure 6");
  77             if (!result[0].equals(source))
  78                 throw new RuntimeException("String.split failure 7");
  79         }
  80         // Check the case for limit == 0, source = "";
  81         // split() now returns 0-length for empty source "" see #6559590
  82         source = "";
  83         String[] result = source.split("e", 0);
  84         if (result.length != 1)
  85             throw new RuntimeException("String.split failure 8");
  86         if (!result[0].equals(source))
  87             throw new RuntimeException("String.split failure 9");
  88 
  89         // check fastpath of String.split()
  90         source = "0123456789abcdefgABCDEFG";
  91         Random r = new Random();
  92 
  93         for (boolean doEscape: new boolean[] {false, true}) {
  94             for (int cp = 0; cp < 0x11000; cp++) {
  95                 Pattern p = null;
  96                 String regex = new String(Character.toChars(cp));
  97                 if (doEscape)
  98                     regex = "\\" + regex;
  99                 try {
 100                     p = Pattern.compile(regex);
 101                 } catch (PatternSyntaxException pse) {
 102                     // illegal syntax
 103                     try {
 104                         "abc".split(regex);
 105                     } catch (PatternSyntaxException pse0) {
 106                         continue;
 107                     }
 108                     throw new RuntimeException("String.split failure 11");
 109                 }
 110                 int off = r.nextInt(source.length());
 111                 String[] srcStrs = new String[] {
 112                     "",
 113                     source,
 114                     regex + source,
 115                     source + regex,
 116                     source.substring(0, 3)
 117                         + regex + source.substring(3, 9)
 118                         + regex + source.substring(9, 15)
 119                         + regex + source.substring(15),
 120                     source.substring(0, off) + regex + source.substring(off)
 121                 };
 122                 for (String src: srcStrs) {
 123                     for (int limit=-2; limit<3; limit++) {
 124                         if (!Arrays.equals(src.split(regex, limit),
 125                                            p.split(src, limit)))
 126                             throw new RuntimeException("String.split failure 12");
 127                     }
 128                 }
 129             }
 130         }
 131     }
 132 }