rev 5902 : 8027754: Enable loop optimizations for loops with MathExact inside

   1 /*
   2  * Copyright (c) 2013, Oracle and/or its affiliates. All rights reserved.
   3  * DO NOT ALTER OR REMOVE COPYRIGHT NOTICES OR THIS FILE HEADER.
   4  *
   5  * This code is free software; you can redistribute it and/or modify it
   6  * under the terms of the GNU General Public License version 2 only, as
   7  * published by the Free Software Foundation.
   8  *
   9  * This code is distributed in the hope that it will be useful, but WITHOUT
  10  * ANY WARRANTY; without even the implied warranty of MERCHANTABILITY or
  11  * FITNESS FOR A PARTICULAR PURPOSE.  See the GNU General Public License
  12  * version 2 for more details (a copy is included in the LICENSE file that
  13  * accompanied this code).
  14  *
  15  * You should have received a copy of the GNU General Public License version
  16  * 2 along with this work; if not, write to the Free Software Foundation,
  17  * Inc., 51 Franklin St, Fifth Floor, Boston, MA 02110-1301 USA.
  18  *
  19  * Please contact Oracle, 500 Oracle Parkway, Redwood Shores, CA 94065 USA
  20  * or visit www.oracle.com if you need additional information or have any
  21  * questions.
  22  */
  23 
  24 /*
  25  * @test
  26  * @bug 8024924
  27  * @summary Test non constant addExact
  28  * @compile AddExactICondTest.java
  29  * @run main AddExactICondTest -XX:+IgnoreUnrecognizedVMOptions -XX:+UnlockExperimentalVMOptions -XX:+UseMathExactIntrinsics
  30  *
  31  */
  32 
  33 public class AddExactICondTest {
  34   public static int result = 0;
  35 
  36   public static void main(String[] args) {
  37     for (int i = 0; i < 50000; ++i) {
  38       runTest();
  39     }
  40   }
  41 
  42   public static void runTest() {
  43     int i = 7;
  44     while (java.lang.Math.addExact(i, result) < 89361) {
  45         if ((java.lang.Math.addExact(i, i) & 1) == 1) {
  46             i += 3;
  47         } else if ((i & 5) == 4) {
  48             i += 7;
  49         } else if ((i & 0xf) == 6) {
  50             i += 2;
  51         } else {
  52             i += 1;
  53         }
  54         result += 2;
  55     }
  56   }
  57 }
--- EOF ---