test/java/math/BigInteger/BigIntegerTest.java

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rev 10672 : 8058505: BigIntegerTest does not exercise Burnikel-Ziegler division
Modify divideLarge() method such that the w/z division exercises the B-Z branch.
Reviewed-by: TBD
Contributed-by: robbiexgibson@yahoo.com

*** 69,78 **** --- 69,79 ---- static final int BITS_TOOM_COOK = 7680; static final int BITS_KARATSUBA_SQUARE = 4096; static final int BITS_TOOM_COOK_SQUARE = 6912; static final int BITS_SCHOENHAGE_BASE = 640; static final int BITS_BURNIKEL_ZIEGLER = 2560; + static final int BITS_BURNIKEL_ZIEGLER_OFFSET = 1280; static final int ORDER_SMALL = 60; static final int ORDER_MEDIUM = 100; // #bits for testing Karatsuba static final int ORDER_KARATSUBA = 2760;
*** 286,308 **** * a specified number of ints in its representation. This test is based on * the observation that if {@code w = u*pow(2,a)} and {@code z = v*pow(2,b)} * where {@code abs(u) > abs(v)} and {@code a > b && b > 0}, then if * {@code w/z = q1*z + r1} and {@code u/v = q2*v + r2}, then * {@code q1 = q2*pow(2,a-b)} and {@code r1 = r2*pow(2,b)}. The test ! * ensures that {@code v} is just under the B-Z threshold and that {@code w} ! * and {@code z} are both over the threshold. This implies that {@code u/v} ! * uses the standard division algorithm and {@code w/z} uses the B-Z ! * algorithm. The results of the two algorithms are then compared using the ! * observation described in the foregoing and if they are not equal a ! * failure is logged. */ public static void divideLarge() { int failCount = 0; ! BigInteger base = BigInteger.ONE.shiftLeft(BITS_BURNIKEL_ZIEGLER - 33); for (int i=0; i<SIZE; i++) { ! BigInteger addend = new BigInteger(BITS_BURNIKEL_ZIEGLER - 34, rnd); BigInteger v = base.add(addend); BigInteger u = v.multiply(BigInteger.valueOf(2 + rnd.nextInt(Short.MAX_VALUE - 1))); if(rnd.nextBoolean()) { --- 287,309 ---- * a specified number of ints in its representation. This test is based on * the observation that if {@code w = u*pow(2,a)} and {@code z = v*pow(2,b)} * where {@code abs(u) > abs(v)} and {@code a > b && b > 0}, then if * {@code w/z = q1*z + r1} and {@code u/v = q2*v + r2}, then * {@code q1 = q2*pow(2,a-b)} and {@code r1 = r2*pow(2,b)}. The test !     * ensures that {@code v} is just under the B-Z threshold, that {@code z} is !     * over the threshold and {@code w} is much larger than {@code z}. This !     * implies that {@code u/v} uses the standard division algorithm and !     * {@code w/z} uses the B-Z algorithm.  The results of the two algorithms !     * are then compared using the observation described in the foregoing and !     * if they are not equal a failure is logged. */ public static void divideLarge() { int failCount = 0; ! BigInteger base = BigInteger.ONE.shiftLeft(BITS_BURNIKEL_ZIEGLER + BITS_BURNIKEL_ZIEGLER_OFFSET - 33); for (int i=0; i<SIZE; i++) { ! BigInteger addend = new BigInteger(BITS_BURNIKEL_ZIEGLER + BITS_BURNIKEL_ZIEGLER_OFFSET - 34, rnd); BigInteger v = base.add(addend); BigInteger u = v.multiply(BigInteger.valueOf(2 + rnd.nextInt(Short.MAX_VALUE - 1))); if(rnd.nextBoolean()) {
*** 310,327 **** } if(rnd.nextBoolean()) { v = v.negate(); } ! int a = 17 + rnd.nextInt(16); int b = 1 + rnd.nextInt(16); ! BigInteger w = u.multiply(BigInteger.valueOf(1L << a)); ! BigInteger z = v.multiply(BigInteger.valueOf(1L << b)); BigInteger[] divideResult = u.divideAndRemainder(v); ! divideResult[0] = divideResult[0].multiply(BigInteger.valueOf(1L << (a - b))); ! divideResult[1] = divideResult[1].multiply(BigInteger.valueOf(1L << b)); BigInteger[] bzResult = w.divideAndRemainder(z); if (divideResult[0].compareTo(bzResult[0]) != 0 || divideResult[1].compareTo(bzResult[1]) != 0) { failCount++; --- 311,328 ---- } if(rnd.nextBoolean()) { v = v.negate(); } ! int a = BITS_BURNIKEL_ZIEGLER_OFFSET + rnd.nextInt(16); int b = 1 + rnd.nextInt(16); ! BigInteger w = u.multiply(BigInteger.ONE.shiftLeft(a)); ! BigInteger z = v.multiply(BigInteger.ONE.shiftLeft(b)); BigInteger[] divideResult = u.divideAndRemainder(v); ! divideResult[0] = divideResult[0].multiply(BigInteger.ONE.shiftLeft(a - b)); ! divideResult[1] = divideResult[1].multiply(BigInteger.ONE.shiftLeft(b)); BigInteger[] bzResult = w.divideAndRemainder(z); if (divideResult[0].compareTo(bzResult[0]) != 0 || divideResult[1].compareTo(bzResult[1]) != 0) { failCount++;