1 /*
   2  * Copyright (c) 1999, 2008, Oracle and/or its affiliates. All rights reserved.
   3  * DO NOT ALTER OR REMOVE COPYRIGHT NOTICES OR THIS FILE HEADER.
   4  *
   5  * This code is free software; you can redistribute it and/or modify it
   6  * under the terms of the GNU General Public License version 2 only, as
   7  * published by the Free Software Foundation.  Oracle designates this
   8  * particular file as subject to the "Classpath" exception as provided
   9  * by Oracle in the LICENSE file that accompanied this code.
  10  *
  11  * This code is distributed in the hope that it will be useful, but WITHOUT
  12  * ANY WARRANTY; without even the implied warranty of MERCHANTABILITY or
  13  * FITNESS FOR A PARTICULAR PURPOSE.  See the GNU General Public License
  14  * version 2 for more details (a copy is included in the LICENSE file that
  15  * accompanied this code).
  16  *
  17  * You should have received a copy of the GNU General Public License version
  18  * 2 along with this work; if not, write to the Free Software Foundation,
  19  * Inc., 51 Franklin St, Fifth Floor, Boston, MA 02110-1301 USA.
  20  *
  21  * Please contact Oracle, 500 Oracle Parkway, Redwood Shores, CA 94065 USA
  22  * or visit www.oracle.com if you need additional information or have any
  23  * questions.
  24  */
  25 
  26 /*
  27  *
  28  * (C) Copyright Taligent, Inc. 1996, 1997 - All Rights Reserved
  29  * (C) Copyright IBM Corp. 1996 - 2002 - All Rights Reserved
  30  *
  31  * The original version of this source code and documentation
  32  * is copyrighted and owned by Taligent, Inc., a wholly-owned
  33  * subsidiary of IBM. These materials are provided under terms
  34  * of a License Agreement between Taligent and Sun. This technology
  35  * is protected by multiple US and International patents.
  36  *
  37  * This notice and attribution to Taligent may not be removed.
  38  * Taligent is a registered trademark of Taligent, Inc.
  39  */
  40 
  41 package java.text;
  42 
  43 import java.util.Vector;
  44 import java.util.Stack;
  45 import java.util.Hashtable;
  46 import java.text.CharacterIterator;
  47 import java.io.InputStream;
  48 import java.io.IOException;
  49 
  50 /**
  51  * A subclass of RuleBasedBreakIterator that adds the ability to use a dictionary
  52  * to further subdivide ranges of text beyond what is possible using just the
  53  * state-table-based algorithm.  This is necessary, for example, to handle
  54  * word and line breaking in Thai, which doesn't use spaces between words.  The
  55  * state-table-based algorithm used by RuleBasedBreakIterator is used to divide
  56  * up text as far as possible, and then contiguous ranges of letters are
  57  * repeatedly compared against a list of known words (i.e., the dictionary)
  58  * to divide them up into words.
  59  *
  60  * DictionaryBasedBreakIterator uses the same rule language as RuleBasedBreakIterator,
  61  * but adds one more special substitution name: <dictionary>.  This substitution
  62  * name is used to identify characters in words in the dictionary.  The idea is that
  63  * if the iterator passes over a chunk of text that includes two or more characters
  64  * in a row that are included in <dictionary>, it goes back through that range and
  65  * derives additional break positions (if possible) using the dictionary.
  66  *
  67  * DictionaryBasedBreakIterator is also constructed with the filename of a dictionary
  68  * file.  It follows a prescribed search path to locate the dictionary (right now,
  69  * it looks for it in /com/ibm/text/resources in each directory in the classpath,
  70  * and won't find it in JAR files, but this location is likely to change).  The
  71  * dictionary file is in a serialized binary format.  We have a very primitive (and
  72  * slow) BuildDictionaryFile utility for creating dictionary files, but aren't
  73  * currently making it public.  Contact us for help.
  74  */
  75 class DictionaryBasedBreakIterator extends RuleBasedBreakIterator {
  76 
  77     /**
  78      * a list of known words that is used to divide up contiguous ranges of letters,
  79      * stored in a compressed, indexed, format that offers fast access
  80      */
  81     private BreakDictionary dictionary;
  82 
  83     /**
  84      * a list of flags indicating which character categories are contained in
  85      * the dictionary file (this is used to determine which ranges of characters
  86      * to apply the dictionary to)
  87      */
  88     private boolean[] categoryFlags;
  89 
  90     /**
  91      * a temporary hiding place for the number of dictionary characters in the
  92      * last range passed over by next()
  93      */
  94     private int dictionaryCharCount;
  95 
  96     /**
  97      * when a range of characters is divided up using the dictionary, the break
  98      * positions that are discovered are stored here, preventing us from having
  99      * to use either the dictionary or the state table again until the iterator
 100      * leaves this range of text
 101      */
 102     private int[] cachedBreakPositions;
 103 
 104     /**
 105      * if cachedBreakPositions is not null, this indicates which item in the
 106      * cache the current iteration position refers to
 107      */
 108     private int positionInCache;
 109 
 110     /**
 111      * Constructs a DictionaryBasedBreakIterator.
 112      * @param description Same as the description parameter on RuleBasedBreakIterator,
 113      * except for the special meaning of "<dictionary>".  This parameter is just
 114      * passed through to RuleBasedBreakIterator's constructor.
 115      * @param dictionaryFilename The filename of the dictionary file to use
 116      */
 117     public DictionaryBasedBreakIterator(String dataFile, String dictionaryFile)
 118                                         throws IOException {
 119         super(dataFile);
 120         byte[] tmp = super.getAdditionalData();
 121         if (tmp != null) {
 122             prepareCategoryFlags(tmp);
 123             super.setAdditionalData(null);
 124         }
 125         dictionary = new BreakDictionary(dictionaryFile);
 126     }
 127 
 128     private void prepareCategoryFlags(byte[] data) {
 129         categoryFlags = new boolean[data.length];
 130         for (int i = 0; i < data.length; i++) {
 131             categoryFlags[i] = (data[i] == (byte)1) ? true : false;
 132         }
 133     }
 134 
 135     public void setText(CharacterIterator newText) {
 136         super.setText(newText);
 137         cachedBreakPositions = null;
 138         dictionaryCharCount = 0;
 139         positionInCache = 0;
 140     }
 141 
 142     /**
 143      * Sets the current iteration position to the beginning of the text.
 144      * (i.e., the CharacterIterator's starting offset).
 145      * @return The offset of the beginning of the text.
 146      */
 147     public int first() {
 148         cachedBreakPositions = null;
 149         dictionaryCharCount = 0;
 150         positionInCache = 0;
 151         return super.first();
 152     }
 153 
 154     /**
 155      * Sets the current iteration position to the end of the text.
 156      * (i.e., the CharacterIterator's ending offset).
 157      * @return The text's past-the-end offset.
 158      */
 159     public int last() {
 160         cachedBreakPositions = null;
 161         dictionaryCharCount = 0;
 162         positionInCache = 0;
 163         return super.last();
 164     }
 165 
 166     /**
 167      * Advances the iterator one step backwards.
 168      * @return The position of the last boundary position before the
 169      * current iteration position
 170      */
 171     public int previous() {
 172         CharacterIterator text = getText();
 173 
 174         // if we have cached break positions and we're still in the range
 175         // covered by them, just move one step backward in the cache
 176         if (cachedBreakPositions != null && positionInCache > 0) {
 177             --positionInCache;
 178             text.setIndex(cachedBreakPositions[positionInCache]);
 179             return cachedBreakPositions[positionInCache];
 180         }
 181 
 182         // otherwise, dump the cache and use the inherited previous() method to move
 183         // backward.  This may fill up the cache with new break positions, in which
 184         // case we have to mark our position in the cache
 185         else {
 186             cachedBreakPositions = null;
 187             int result = super.previous();
 188             if (cachedBreakPositions != null) {
 189                 positionInCache = cachedBreakPositions.length - 2;
 190             }
 191             return result;
 192         }
 193     }
 194 
 195     /**
 196      * Sets the current iteration position to the last boundary position
 197      * before the specified position.
 198      * @param offset The position to begin searching from
 199      * @return The position of the last boundary before "offset"
 200      */
 201     public int preceding(int offset) {
 202         CharacterIterator text = getText();
 203         checkOffset(offset, text);
 204 
 205         // if we have no cached break positions, or "offset" is outside the
 206         // range covered by the cache, we can just call the inherited routine
 207         // (which will eventually call other routines in this class that may
 208         // refresh the cache)
 209         if (cachedBreakPositions == null || offset <= cachedBreakPositions[0] ||
 210                 offset > cachedBreakPositions[cachedBreakPositions.length - 1]) {
 211             cachedBreakPositions = null;
 212             return super.preceding(offset);
 213         }
 214 
 215         // on the other hand, if "offset" is within the range covered by the cache,
 216         // then all we have to do is search the cache for the last break position
 217         // before "offset"
 218         else {
 219             positionInCache = 0;
 220             while (positionInCache < cachedBreakPositions.length
 221                    && offset > cachedBreakPositions[positionInCache]) {
 222                 ++positionInCache;
 223             }
 224             --positionInCache;
 225             text.setIndex(cachedBreakPositions[positionInCache]);
 226             return text.getIndex();
 227         }
 228     }
 229 
 230     /**
 231      * Sets the current iteration position to the first boundary position after
 232      * the specified position.
 233      * @param offset The position to begin searching forward from
 234      * @return The position of the first boundary after "offset"
 235      */
 236     public int following(int offset) {
 237         CharacterIterator text = getText();
 238         checkOffset(offset, text);
 239 
 240         // if we have no cached break positions, or if "offset" is outside the
 241         // range covered by the cache, then dump the cache and call our
 242         // inherited following() method.  This will call other methods in this
 243         // class that may refresh the cache.
 244         if (cachedBreakPositions == null || offset < cachedBreakPositions[0] ||
 245                 offset >= cachedBreakPositions[cachedBreakPositions.length - 1]) {
 246             cachedBreakPositions = null;
 247             return super.following(offset);
 248         }
 249 
 250         // on the other hand, if "offset" is within the range covered by the
 251         // cache, then just search the cache for the first break position
 252         // after "offset"
 253         else {
 254             positionInCache = 0;
 255             while (positionInCache < cachedBreakPositions.length
 256                    && offset >= cachedBreakPositions[positionInCache]) {
 257                 ++positionInCache;
 258             }
 259             text.setIndex(cachedBreakPositions[positionInCache]);
 260             return text.getIndex();
 261         }
 262     }
 263 
 264     /**
 265      * This is the implementation function for next().
 266      */
 267     protected int handleNext() {
 268         CharacterIterator text = getText();
 269 
 270         // if there are no cached break positions, or if we've just moved
 271         // off the end of the range covered by the cache, we have to dump
 272         // and possibly regenerate the cache
 273         if (cachedBreakPositions == null ||
 274             positionInCache == cachedBreakPositions.length - 1) {
 275 
 276             // start by using the inherited handleNext() to find a tentative return
 277             // value.   dictionaryCharCount tells us how many dictionary characters
 278             // we passed over on our way to the tentative return value
 279             int startPos = text.getIndex();
 280             dictionaryCharCount = 0;
 281             int result = super.handleNext();
 282 
 283             // if we passed over more than one dictionary character, then we use
 284             // divideUpDictionaryRange() to regenerate the cached break positions
 285             // for the new range
 286             if (dictionaryCharCount > 1 && result - startPos > 1) {
 287                 divideUpDictionaryRange(startPos, result);
 288             }
 289 
 290             // otherwise, the value we got back from the inherited fuction
 291             // is our return value, and we can dump the cache
 292             else {
 293                 cachedBreakPositions = null;
 294                 return result;
 295             }
 296         }
 297 
 298         // if the cache of break positions has been regenerated (or existed all
 299         // along), then just advance to the next break position in the cache
 300         // and return it
 301         if (cachedBreakPositions != null) {
 302             ++positionInCache;
 303             text.setIndex(cachedBreakPositions[positionInCache]);
 304             return cachedBreakPositions[positionInCache];
 305         }
 306         return -9999;   // SHOULD NEVER GET HERE!
 307     }
 308 
 309     /**
 310      * Looks up a character category for a character.
 311      */
 312     protected int lookupCategory(int c) {
 313         // this override of lookupCategory() exists only to keep track of whether we've
 314         // passed over any dictionary characters.  It calls the inherited lookupCategory()
 315         // to do the real work, and then checks whether its return value is one of the
 316         // categories represented in the dictionary.  If it is, bump the dictionary-
 317         // character count.
 318         int result = super.lookupCategory(c);
 319         if (result != RuleBasedBreakIterator.IGNORE && categoryFlags[result]) {
 320             ++dictionaryCharCount;
 321         }
 322         return result;
 323     }
 324 
 325     /**
 326      * This is the function that actually implements the dictionary-based
 327      * algorithm.  Given the endpoints of a range of text, it uses the
 328      * dictionary to determine the positions of any boundaries in this
 329      * range.  It stores all the boundary positions it discovers in
 330      * cachedBreakPositions so that we only have to do this work once
 331      * for each time we enter the range.
 332      */
 333     private void divideUpDictionaryRange(int startPos, int endPos) {
 334         CharacterIterator text = getText();
 335 
 336         // the range we're dividing may begin or end with non-dictionary characters
 337         // (i.e., for line breaking, we may have leading or trailing punctuation
 338         // that needs to be kept with the word).  Seek from the beginning of the
 339         // range to the first dictionary character
 340         text.setIndex(startPos);
 341         int c = getCurrent();
 342         int category = lookupCategory(c);
 343         while (category == IGNORE || !categoryFlags[category]) {
 344             c = getNext();
 345             category = lookupCategory(c);
 346         }
 347 
 348         // initialize.  We maintain two stacks: currentBreakPositions contains
 349         // the list of break positions that will be returned if we successfully
 350         // finish traversing the whole range now.  possibleBreakPositions lists
 351         // all other possible word ends we've passed along the way.  (Whenever
 352         // we reach an error [a sequence of characters that can't begin any word
 353         // in the dictionary], we back up, possibly delete some breaks from
 354         // currentBreakPositions, move a break from possibleBreakPositions
 355         // to currentBreakPositions, and start over from there.  This process
 356         // continues in this way until we either successfully make it all the way
 357         // across the range, or exhaust all of our combinations of break
 358         // positions.)
 359         Stack<Integer> currentBreakPositions = new Stack<>();
 360         Stack<Integer> possibleBreakPositions = new Stack<>();
 361         Vector<Integer> wrongBreakPositions = new Vector<>();
 362 
 363         // the dictionary is implemented as a trie, which is treated as a state
 364         // machine.  -1 represents the end of a legal word.  Every word in the
 365         // dictionary is represented by a path from the root node to -1.  A path
 366         // that ends in state 0 is an illegal combination of characters.
 367         int state = 0;
 368 
 369         // these two variables are used for error handling.  We keep track of the
 370         // farthest we've gotten through the range being divided, and the combination
 371         // of breaks that got us that far.  If we use up all possible break
 372         // combinations, the text contains an error or a word that's not in the
 373         // dictionary.  In this case, we "bless" the break positions that got us the
 374         // farthest as real break positions, and then start over from scratch with
 375         // the character where the error occurred.
 376         int farthestEndPoint = text.getIndex();
 377         Stack<Integer> bestBreakPositions = null;
 378 
 379         // initialize (we always exit the loop with a break statement)
 380         c = getCurrent();
 381         while (true) {
 382 
 383             // if we can transition to state "-1" from our current state, we're
 384             // on the last character of a legal word.  Push that position onto
 385             // the possible-break-positions stack
 386             if (dictionary.getNextState(state, 0) == -1) {
 387                 possibleBreakPositions.push(Integer.valueOf(text.getIndex()));
 388             }
 389 
 390             // look up the new state to transition to in the dictionary
 391             state = dictionary.getNextStateFromCharacter(state, c);
 392 
 393             // if the character we're sitting on causes us to transition to
 394             // the "end of word" state, then it was a non-dictionary character
 395             // and we've successfully traversed the whole range.  Drop out
 396             // of the loop.
 397             if (state == -1) {
 398                 currentBreakPositions.push(Integer.valueOf(text.getIndex()));
 399                 break;
 400             }
 401 
 402             // if the character we're sitting on causes us to transition to
 403             // the error state, or if we've gone off the end of the range
 404             // without transitioning to the "end of word" state, we've hit
 405             // an error...
 406             else if (state == 0 || text.getIndex() >= endPos) {
 407 
 408                 // if this is the farthest we've gotten, take note of it in
 409                 // case there's an error in the text
 410                 if (text.getIndex() > farthestEndPoint) {
 411                     farthestEndPoint = text.getIndex();
 412 
 413                     @SuppressWarnings("unchecked")
 414                     Stack<Integer> currentBreakPositionsCopy = (Stack<Integer>) currentBreakPositions.clone();
 415 
 416                     bestBreakPositions = currentBreakPositionsCopy;
 417                 }
 418 
 419                 // wrongBreakPositions is a list of all break positions
 420                 // we've tried starting that didn't allow us to traverse
 421                 // all the way through the text.  Every time we pop a
 422                 //break position off of currentBreakPositions, we put it
 423                 // into wrongBreakPositions to avoid trying it again later.
 424                 // If we make it to this spot, we're either going to back
 425                 // up to a break in possibleBreakPositions and try starting
 426                 // over from there, or we've exhausted all possible break
 427                 // positions and are going to do the fallback procedure.
 428                 // This loop prevents us from messing with anything in
 429                 // possibleBreakPositions that didn't work as a starting
 430                 // point the last time we tried it (this is to prevent a bunch of
 431                 // repetitive checks from slowing down some extreme cases)
 432                 Integer newStartingSpot = null;
 433                 while (!possibleBreakPositions.isEmpty() && wrongBreakPositions.contains(
 434                             possibleBreakPositions.peek())) {
 435                     possibleBreakPositions.pop();
 436                 }
 437 
 438                 // if we've used up all possible break-position combinations, there's
 439                 // an error or an unknown word in the text.  In this case, we start
 440                 // over, treating the farthest character we've reached as the beginning
 441                 // of the range, and "blessing" the break positions that got us that
 442                 // far as real break positions
 443                 if (possibleBreakPositions.isEmpty()) {
 444                     if (bestBreakPositions != null) {
 445                         currentBreakPositions = bestBreakPositions;
 446                         if (farthestEndPoint < endPos) {
 447                             text.setIndex(farthestEndPoint + 1);
 448                         }
 449                         else {
 450                             break;
 451                         }
 452                     }
 453                     else {
 454                         if ((currentBreakPositions.size() == 0 ||
 455                              currentBreakPositions.peek().intValue() != text.getIndex())
 456                             && text.getIndex() != startPos) {
 457                             currentBreakPositions.push(new Integer(text.getIndex()));
 458                         }
 459                         getNext();
 460                         currentBreakPositions.push(new Integer(text.getIndex()));
 461                     }
 462                 }
 463 
 464                 // if we still have more break positions we can try, then promote the
 465                 // last break in possibleBreakPositions into currentBreakPositions,
 466                 // and get rid of all entries in currentBreakPositions that come after
 467                 // it.  Then back up to that position and start over from there (i.e.,
 468                 // treat that position as the beginning of a new word)
 469                 else {
 470                     Integer temp = possibleBreakPositions.pop();
 471                     Integer temp2 = null;
 472                     while (!currentBreakPositions.isEmpty() && temp.intValue() <
 473                            currentBreakPositions.peek().intValue()) {
 474                         temp2 = currentBreakPositions.pop();
 475                         wrongBreakPositions.addElement(temp2);
 476                     }
 477                     currentBreakPositions.push(temp);
 478                     text.setIndex(currentBreakPositions.peek().intValue());
 479                 }
 480 
 481                 // re-sync "c" for the next go-round, and drop out of the loop if
 482                 // we've made it off the end of the range
 483                 c = getCurrent();
 484                 if (text.getIndex() >= endPos) {
 485                     break;
 486                 }
 487             }
 488 
 489             // if we didn't hit any exceptional conditions on this last iteration,
 490             // just advance to the next character and loop
 491             else {
 492                 c = getNext();
 493             }
 494         }
 495 
 496         // dump the last break position in the list, and replace it with the actual
 497         // end of the range (which may be the same character, or may be further on
 498         // because the range actually ended with non-dictionary characters we want to
 499         // keep with the word)
 500         if (!currentBreakPositions.isEmpty()) {
 501             currentBreakPositions.pop();
 502         }
 503         currentBreakPositions.push(Integer.valueOf(endPos));
 504 
 505         // create a regular array to hold the break positions and copy
 506         // the break positions from the stack to the array (in addition,
 507         // our starting position goes into this array as a break position).
 508         // This array becomes the cache of break positions used by next()
 509         // and previous(), so this is where we actually refresh the cache.
 510         cachedBreakPositions = new int[currentBreakPositions.size() + 1];
 511         cachedBreakPositions[0] = startPos;
 512 
 513         for (int i = 0; i < currentBreakPositions.size(); i++) {
 514             cachedBreakPositions[i + 1] = currentBreakPositions.elementAt(i).intValue();
 515         }
 516         positionInCache = 0;
 517     }
 518 }