6 * under the terms of the GNU General Public License version 2 only, as
7 * published by the Free Software Foundation.
8 *
9 * This code is distributed in the hope that it will be useful, but WITHOUT
10 * ANY WARRANTY; without even the implied warranty of MERCHANTABILITY or
11 * FITNESS FOR A PARTICULAR PURPOSE. See the GNU General Public License
12 * version 2 for more details (a copy is included in the LICENSE file that
13 * accompanied this code).
14 *
15 * You should have received a copy of the GNU General Public License version
16 * 2 along with this work; if not, write to the Free Software Foundation,
17 * Inc., 51 Franklin St, Fifth Floor, Boston, MA 02110-1301 USA.
18 *
19 * Please contact Oracle, 500 Oracle Parkway, Redwood Shores, CA 94065 USA
20 * or visit www.oracle.com if you need additional information or have any
21 * questions.
22 */
23
24 /**
25 * @test
26 * @bug 6840246
27 * @summary test String.split()
28 */
29 import java.util.Arrays;
30 import java.util.Random;
31 import java.util.regex.*;
32
33 public class Split {
34
35 public static void main(String[] args) throws Exception {
36 String source = "0123456789";
37
38 for (int limit=-2; limit<3; limit++) {
39 for (int x=0; x<10; x++) {
40 String[] result = source.split(Integer.toString(x), limit);
41 int expectedLength = limit < 1 ? 2 : limit;
42
43 if ((limit == 0) && (x == 9)) {
44 // expected dropping of ""
45 if (result.length != 1)
46 throw new RuntimeException("String.split failure 1");
61 "String.split failure 10");
62 }
63 }
64 }
65 if (expectedLength > 1) { // Check segment 2
66 if (!result[1].equals(source.substring(x+1,10)))
67 throw new RuntimeException("String.split failure 5");
68 }
69 }
70 }
71 }
72 // Check the case for no match found
73 for (int limit=-2; limit<3; limit++) {
74 String[] result = source.split("e", limit);
75 if (result.length != 1)
76 throw new RuntimeException("String.split failure 6");
77 if (!result[0].equals(source))
78 throw new RuntimeException("String.split failure 7");
79 }
80 // Check the case for limit == 0, source = "";
81 source = "";
82 String[] result = source.split("e", 0);
83 if (result.length != 1)
84 throw new RuntimeException("String.split failure 8");
85 if (!result[0].equals(source))
86 throw new RuntimeException("String.split failure 9");
87
88 // check fastpath of String.split()
89 source = "0123456789abcdefgABCDEFG";
90 Random r = new Random();
91
92 for (boolean doEscape: new boolean[] {false, true}) {
93 for (int cp = 0; cp < 0x11000; cp++) {
94 Pattern p = null;
95 String regex = new String(Character.toChars(cp));
96 if (doEscape)
97 regex = "\\" + regex;
98 try {
99 p = Pattern.compile(regex);
100 } catch (PatternSyntaxException pse) {
101 // illegal syntax
102 try {
103 "abc".split(regex);
104 } catch (PatternSyntaxException pse0) {
105 continue;
106 }
|
6 * under the terms of the GNU General Public License version 2 only, as
7 * published by the Free Software Foundation.
8 *
9 * This code is distributed in the hope that it will be useful, but WITHOUT
10 * ANY WARRANTY; without even the implied warranty of MERCHANTABILITY or
11 * FITNESS FOR A PARTICULAR PURPOSE. See the GNU General Public License
12 * version 2 for more details (a copy is included in the LICENSE file that
13 * accompanied this code).
14 *
15 * You should have received a copy of the GNU General Public License version
16 * 2 along with this work; if not, write to the Free Software Foundation,
17 * Inc., 51 Franklin St, Fifth Floor, Boston, MA 02110-1301 USA.
18 *
19 * Please contact Oracle, 500 Oracle Parkway, Redwood Shores, CA 94065 USA
20 * or visit www.oracle.com if you need additional information or have any
21 * questions.
22 */
23
24 /**
25 * @test
26 * @bug 6840246 6559590
27 * @summary test String.split()
28 */
29 import java.util.Arrays;
30 import java.util.Random;
31 import java.util.regex.*;
32
33 public class Split {
34
35 public static void main(String[] args) throws Exception {
36 String source = "0123456789";
37
38 for (int limit=-2; limit<3; limit++) {
39 for (int x=0; x<10; x++) {
40 String[] result = source.split(Integer.toString(x), limit);
41 int expectedLength = limit < 1 ? 2 : limit;
42
43 if ((limit == 0) && (x == 9)) {
44 // expected dropping of ""
45 if (result.length != 1)
46 throw new RuntimeException("String.split failure 1");
61 "String.split failure 10");
62 }
63 }
64 }
65 if (expectedLength > 1) { // Check segment 2
66 if (!result[1].equals(source.substring(x+1,10)))
67 throw new RuntimeException("String.split failure 5");
68 }
69 }
70 }
71 }
72 // Check the case for no match found
73 for (int limit=-2; limit<3; limit++) {
74 String[] result = source.split("e", limit);
75 if (result.length != 1)
76 throw new RuntimeException("String.split failure 6");
77 if (!result[0].equals(source))
78 throw new RuntimeException("String.split failure 7");
79 }
80 // Check the case for limit == 0, source = "";
81 // split() now returns 0-length for empty source "" see #6559590
82 source = "";
83 String[] result = source.split("e", 0);
84 if (result.length != 0)
85 throw new RuntimeException("String.split failure 8");
86
87 // check fastpath of String.split()
88 source = "0123456789abcdefgABCDEFG";
89 Random r = new Random();
90
91 for (boolean doEscape: new boolean[] {false, true}) {
92 for (int cp = 0; cp < 0x11000; cp++) {
93 Pattern p = null;
94 String regex = new String(Character.toChars(cp));
95 if (doEscape)
96 regex = "\\" + regex;
97 try {
98 p = Pattern.compile(regex);
99 } catch (PatternSyntaxException pse) {
100 // illegal syntax
101 try {
102 "abc".split(regex);
103 } catch (PatternSyntaxException pse0) {
104 continue;
105 }
|